You might also find something like this useful. (I know it's already solved,
but this is a wholly different approach)
cat file | while read line
do
mystuff $line
done
I have also seen scripts where 'read' will parse a IFS-delimited line into
multiple variables for you. Example: CSV (comma-separated values) file:
Jones,Tim,123-12-1234
Foster,Paul,234-23-2345
shell script to re-arrange the fields (w/o commas)
export IFS=,
cat text.csv | while read lname fname ssn
do
echo $ssn $fname $lname
done
Just tried it out, tastes great, less filling!
If there are more than 3 fields in this example, all the extra fields will be
assigned to the last variable (ssn in my example). If there aren't enough
fields, the unused ones will be blank.
You could combine both methods if you really wanted:
export IFS=,
cat text.csv | while read line
do
echo new record has `echo $line | wc -w | bc` fields
# bc strips of wc's extra spaces
for field in $line
do
echo field: $field
done
done
tlj
El Jue 07 Ago 2003 02:07 AM, Paul M Foster escribió:
> On Thu, Aug 07, 2003 at 12:38:49AM -0400, Paul M Foster wrote:
> > Within a bash script, I'm trying to feed each line of a file into a
> > variable, to wit:
> >
> > for line in `cat file`
> > do
> > do_whatever
> > done
> >
> > At the end of this operation, I want the $line variable to equal the
> > contents of a single line in the file. The problem is that the shell
> > breaks the line into _words_ if there are any spaces, tabs or newlines
> > in it. I understand why. It's because of the value of the IFS shell
> > variable. To get around this, I want to set the IFS variable to be
> > _only_ the newline. But I can't find a way to do it. The following do
> > not work:
> >
> > IFS=
> >
> > IFS=\n
> > IFS='\n'
> > IFS="\n"
>
> The answer (to set IFS to only a newline) is:
>
> IFS='
> '
>
> Paul
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