Eben King wrote:
>How can I find how much memory allocated to a process is swapped out? Or
>is the only way to kill the process and see how much swap usage goes down?
>I run W2K inside of VMware, and VMware (according to top) is currently
>using 162 MB (out of 768 MB). Often, tasks take a long time to start in
>VMware (raise a menu, start a process, etc.), but once started, proceed at
>normal speed. I think that's because VMware is partially swapped out,
>which in turn is because I don't have enough RAM. I suppose I could infer
>which "memory" accesses are really swap reads by the time taken for them.
>
>When W2K accesses part of its 600 MB of real (it thinks) RAM, part of that
>RAM has been swapped out by the host OS. Had it been swapped out by W2K,
>presumably W2K could've optimized things so it acted better.
>
>Should I lower VMware's memory allocation to match what it really gets in
>the mean time?
>
>
>
I think that you can tell how much of a processes' memory is swapped-out
by subtracting RSS from SIZE (SIZE is the total memory for the process
and RSS is the portion of memory that is not swapped-out (Resident Set
Size???). Note that there is a small discrepency that you probably don't
care about (from the man page for 'top'):
The SIZE and RSS fields don't count the page tables and the task_struct
of a process;
this is at least 12K of memory that is always resident. SIZE is the
virtual size of the process
(code+data+stack).
--ronan
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