> printf "argument= %s\n" "$1" #works correctly
> if [$1 -eq ""]; then
> cnt=10
> printf "$1 is blank\n" "$cnt"
> else
> printf "$1 is not blank\n" "$cnt"
> cnt=$1
> fi
> printf "cnt=%s\n" $cnt
> Error:
> If there is no argument I get this message: line 9: -eq: command not found
> If there is an argument of 15: line 9: 15: command not found
> Anyone have any idea what I am doing wrong? line 9 is the 'if' statement
#!/bin/bash
# /usr/local/bin/bed
# by Ron KA4INM Youvan
if
Here my "if" is on line #4, is that right?
if there is no command -eq you may need to put -e -q
My "bash" book is for version 2.0 so it is out of date.
--
Ron KA4INM - The harder I work, the behinder I get!
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