quote the $1 as in "$1"
---------------------------------------------------------------
James Forte, Magna Timeshare Software
http://www.magna.net/ mailto:James@Magna.Net
-----------------------------------------------------------------
On Sat, 17 May 2008, Ron Youvan wrote:
>> printf "argument= %s\n" "$1" #works
>> correctly
>
>> if [$1 -eq ""]; then
>> cnt=10
>> printf "$1 is blank\n" "$cnt" else
>> printf "$1 is not blank\n" "$cnt"
>> cnt=$1
>> fi
>
>> printf "cnt=%s\n" $cnt
>
>> Error: If there is no argument I get this message: line
>> 9: -eq: command not found
>> If there is an argument of 15: line 9: 15: command not
>> found
>
>> Anyone have any idea what I am doing wrong? line 9 is
>> the 'if' statement
>
>
> #!/bin/bash
> # /usr/local/bin/bed
> # by Ron KA4INM Youvan
> if
>
> Here my "if" is on line #4, is that right?
> if there is no command -eq you may need to put -e -q
>
> My "bash" book is for version 2.0 so it is out of date.
>
>
> --
> Ron KA4INM - The harder I work, the behinder I get!
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